y^2-(5/3)y=(-25/36)

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Solution for y^2-(5/3)y=(-25/36) equation: 


y in (-oo:+oo)

y^2-((5/3)*y) = -25/36 // + -25/36

y^2-((5/3)*y)-(-25/36) = 0

y^2+(-5/3)*y+25/36 = 0

y^2-5/3*y+25/36 = 0

DELTA = (-5/3)^2-(25/36*1*4)

DELTA = 0

y = 5/3/(1*2)

y = 5/6 or y = 5/6

y in { 5/6, 5/6 }

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